
\begin{enumerate}
\item $\ln\big(\e^{2x}\big) = \boxed{2x}$ car $\ln\big(\e^X\big) = X$, quel que soit $X$.

\item $\ln\big(\e^{2x-4}\big)-\ln\big(\e^{2x+4}\big) = 2x-4-(2x+4)=\boxed{-8}$.

\item $\dfrac{3\ln\big(\e^{x+1}\big)}{2\ln\big(\e^{1-x}\big)} = \dfrac{3(x+1)}{2(1-x)}=\boxed{\dfrac{3x+3}{2-2x}}$.
\end{enumerate}
