
        \setlength{\parindent}{0pt}
        Voici le tableau donnant $\Phi(t)=\mathbb{P}(X<t)$ dans le cas $t\in[0;2.99]$~:
        {\small

        \begin{center}\begin{tabular}{|c|c|c|>{\columncolor[gray]{0.7}}c|c|c|c|c|c|c|c|}\hline t &0.0&0.01&0.02&0.03&0.04&0.05&0.06&0.07&0.08&0.09\\\hline0.0&0.5&0.50399&0.50798&0.51197&0.51595&0.51994&0.52392&0.5279&0.53188&0.53586 \\ 0.1&0.53983&0.5438&0.54776&0.55172&0.55567&0.55962&0.56356&0.56749&0.57142&0.57535 \\ 0.2&0.57926&0.58317&0.58706&0.59095&0.59483&0.59871&0.60257&0.60642&0.61026&0.61409 \\ 0.3&0.61791&0.62172&0.62552&0.6293&0.63307&0.63683&0.64058&0.64431&0.64803&0.65173 \\ 0.4&0.65542&0.6591&0.66276&0.6664&0.67003&0.67364&0.67724&0.68082&0.68439&0.68793 \\ 0.5&0.69146&0.69497&0.69847&0.70194&0.7054&0.70884&0.71226&0.71566&0.71904&0.7224 \\ 0.6&0.72575&0.72907&0.73237&0.73565&0.73891&0.74215&0.74537&0.74857&0.75175&0.7549 \\ 0.7&0.75804&0.76115&0.76424&0.7673&0.77035&0.77337&0.77637&0.77935&0.7823&0.78524 \\ 0.8&0.78814&0.79103&0.79389&0.79673&0.79955&0.80234&0.80511&0.80785&0.81057&0.81327 \\ 0.9&0.81594&0.81859&0.82121&0.82381&0.82639&0.82894&0.83147&0.83398&0.83646&0.83891\\\hline1.0&0.84134&0.84375&0.84614&0.84849&0.85083&0.85314&0.85543&0.85769&0.85993&0.86214 \\ 1.1&0.86433&0.8665&0.86864&0.87076&0.87286&0.87493&0.87698&0.879&0.881&0.88298 \\ 1.2&0.88493&0.88686&0.88877&0.89065&0.89251&0.89435&0.89617&0.89796&0.89973&0.90147 \\ 1.3&0.9032&0.9049&0.90658&0.90824&0.90988&0.91149&0.91309&0.91466&0.91621&0.91774 \\ 1.4&0.91924&0.92073&0.9222&0.92364&0.92507&0.92647&0.92785&0.92922&0.93056&0.93189 \\ 1.5&0.93319&0.93448&0.93574&0.93699&0.93822&0.93943&0.94062&0.94179&0.94295&0.94408 \\ 1.6&0.9452&0.9463&0.94738&0.94845&0.9495&0.95053&0.95154&0.95254&0.95352&0.95449 \\ 1.7&0.95543&0.95637&0.95728&0.95818&0.95907&0.95994&0.9608&0.96164&0.96246&0.96327 \\ 1.8&0.96407&0.96485&0.96562&0.96638&0.96712&0.96784&0.96856&0.96926&0.96995&0.97062 \\ \rowcolor[gray]{0.7}1.9&0.97128&0.97193&0.97257&0.9732&0.97381&0.97441&0.975&0.97558&0.97615&0.9767\\\hline2.0&0.97725&0.97778&0.97831&0.97882&0.97932&0.97982&0.9803&0.98077&0.98124&0.98169 \\ 2.1&0.98214&0.98257&0.983&0.98341&0.98382&0.98422&0.98461&0.985&0.98537&0.98574 \\ 2.2&0.9861&0.98645&0.98679&0.98713&0.98745&0.98778&0.98809&0.9884&0.9887&0.98899 \\ 2.3&0.98928&0.98956&0.98983&0.9901&0.99036&0.99061&0.99086&0.99111&0.99134&0.99158 \\ 2.4&0.9918&0.99202&0.99224&0.99245&0.99266&0.99286&0.99305&0.99324&0.99343&0.99361 \\ 2.5&0.99379&0.99396&0.99413&0.9943&0.99446&0.99461&0.99477&0.99492&0.99506&0.9952 \\ 2.6&0.99534&0.99547&0.9956&0.99573&0.99585&0.99598&0.99609&0.99621&0.99632&0.99643 \\ 2.7&0.99653&0.99664&0.99674&0.99683&0.99693&0.99702&0.99711&0.9972&0.99728&0.99736 \\ 2.8&0.99744&0.99752&0.9976&0.99767&0.99774&0.99781&0.99788&0.99795&0.99801&0.99807 \\ 2.9&0.99813&0.99819&0.99825&0.99831&0.99836&0.99841&0.99846&0.99851&0.99856&0.99861\\\hline\end{tabular}
        \end{center}
        }
        \bigskip

        On   veut   calculer    $\mathbb{P}(X<1.96)$   sachant   que   $X\sim
        \mathcal{N}(1,0.5)$.
        Comme la variable r\'eduite $T=\frac{X-1}{0.5}$ suit la loi $\mathcal{N}(0,1)$ alors $X<1.96$
        \'equivaut \`a $T<1.92$.

        On lit dans la table de la loi normale
        $\mathbb{P}(T<1.92)\approx
        \mathbb{P}(T<1.92)\approx
         0.97257$.