
\begin{enumerate}
\item $I=\intervOF{-3}{7}$ et $J=\intervFO{-1}{+\infty}$

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -5,0) -- (9,0);
\begin{scope}[draw=blue]
\draw[thick] (-3,0) -- (7,0);
\draw[thick] (-3.1,0.1) -- (-3.0,0.1) -- (-3.0,-0.1) -- (-3.1,-0.1);
\draw[thick] (6.9,0.1) -- (7.0,0.1) -- (7.0,-0.1) -- (6.9,-0.1);
\node[below,inner sep=3mm] at (-3,0) {$-3$};
\node[below,inner sep=3mm] at (7,0) {$7$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (-1,-0.03) -- (9,-0.03);
\draw[thick] (-0.9,0.1) -- (-1.0,0.1) -- (-1.0,-0.1) -- (-0.9,-0.1);
\draw[thick] (9.1,0.1) -- (9.0,0.1) -- (9.0,-0.1) -- (9.1,-0.1);
\node[below,inner sep=3mm] at (-1,0) {$-1$};
\node[below,inner sep=3mm] at (9,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFF{-1}{7}$ et $I \cup J = \intervOO{-3}{+\infty}$.


%%%%%%%%%%%%%%%%%%%

\item $I=\intervOO{-\infty}{4}$ et $J=\intervFF{4}{10}$

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( 2,0) -- (12,0);
\begin{scope}[draw=blue]
\draw[thick] (2,0) -- (4,0);
\draw[thick] (1.9,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (1.9,-0.1);
\draw[thick] (4.1,0.1) -- (4.0,0.1) -- (4.0,-0.1) -- (4.1,-0.1);
\node[below,inner sep=3mm] at (2,0) {$-\infty$};
\node[below,inner sep=3mm] at (4,0) {$4$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (4,-0.03) -- (10,-0.03);
\draw[thick] (4.1,0.1) -- (4.0,0.1) -- (4.0,-0.1) -- (4.1,-0.1);
\draw[thick] (9.9,0.1) -- (10.0,0.1) -- (10.0,-0.1) -- (9.9,-0.1);
\node[below,inner sep=3mm] at (4,0) {$4$};
\node[below,inner sep=3mm] at (10,0) {$10$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \varnothing$ et $I \cup J = \intervOF{-\infty}{10}$.

%%%%%%%%%%%%%%%%%%

\item $I=\intervFF{-10}{2}$ et $J=\intervFF{-3}{7}$

\begin{tikzpicture}[scale=0.7142857142857143, every node/.style={scale=0.7142857142857143}]
\draw[->,>=latex] ( -12,0) -- (9,0);
\begin{scope}[draw=blue]
\draw[thick] (-10,0) -- (2,0);
\draw[thick] (-9.9,0.1) -- (-10.0,0.1) -- (-10.0,-0.1) -- (-9.9,-0.1);
\draw[thick] (1.9,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (1.9,-0.1);
\node[below,inner sep=3mm] at (-10,0) {$-10$};
\node[below,inner sep=3mm] at (2,0) {$2$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (-3,-0.03) -- (7,-0.03);
\draw[thick] (-2.9,0.1) -- (-3.0,0.1) -- (-3.0,-0.1) -- (-2.9,-0.1);
\draw[thick] (6.9,0.1) -- (7.0,0.1) -- (7.0,-0.1) -- (6.9,-0.1);
\node[below,inner sep=3mm] at (-3,0) {$-3$};
\node[below,inner sep=3mm] at (7,0) {$7$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFF{-3}{2}$ et $I \cup J = \intervFF{-10}{7}$.

%%%%%%%%%%%%%%%%%

\item $I=\intervOF{-\infty}{3}$ et $J=\intervFO{-6}{+\infty}$ % 4

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -8,0) -- (5,0);
\begin{scope}[draw=blue]
\draw[thick] (-8,0) -- (3,0);
\draw[thick] (-8.1,0.1) -- (-8.0,0.1) -- (-8.0,-0.1) -- (-8.1,-0.1);
\draw[thick] (2.9,0.1) -- (3.0,0.1) -- (3.0,-0.1) -- (2.9,-0.1);
\node[below,inner sep=3mm] at (-8,0) {$-\infty$};
\node[below,inner sep=3mm] at (3,0) {$3$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (-6,-0.03) -- (5,-0.03);
\draw[thick] (-5.9,0.1) -- (-6.0,0.1) -- (-6.0,-0.1) -- (-5.9,-0.1);
\draw[thick] (5.1,0.1) -- (5.0,0.1) -- (5.0,-0.1) -- (5.1,-0.1);
\node[below,inner sep=3mm] at (-6,0) {$-6$};
\node[below,inner sep=3mm] at (5,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFF{-6}{3}$ et $I \cup J = \R$.

%%%%%%%%%%%%%%%%%%

\item $I=\intervFO{7}{+\infty}$ et $J=\intervFO{-5}{+\infty}$ % 5

\begin{tikzpicture}[scale=0.9375, every node/.style={scale=0.9375}]
\draw[->,>=latex] ( -7,0) -- (9,0);
\begin{scope}[draw=blue]
\draw[thick] (7,0) -- (9,0);
\draw[thick] (7.1,0.1) -- (7.0,0.1) -- (7.0,-0.1) -- (7.1,-0.1);
\draw[thick] (9.1,0.1) -- (9.0,0.1) -- (9.0,-0.1) -- (9.1,-0.1);
\node[below,inner sep=3mm] at (7,0) {$7$};
\node[below,inner sep=3mm] at (9,0) {$+\infty$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (-5,-0.03) -- (9,-0.03);
\draw[thick] (-4.9,0.1) -- (-5.0,0.1) -- (-5.0,-0.1) -- (-4.9,-0.1);
\draw[thick] (9.1,0.1) -- (9.0,0.1) -- (9.0,-0.1) -- (9.1,-0.1);
\node[below,inner sep=3mm] at (-5,0) {$-5$};
\node[below,inner sep=3mm] at (9,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFO{7}{+\infty}$ et $I \cup J = \intervFO{-5}{+\infty}$.

%%%%%%%%%%%%%%%%%%%

\item $I=\intervOF{3}{18}$ et $J=\intervOF{17}{20}$ % 6

\begin{tikzpicture}[scale=0.7142857142857143, every node/.style={scale=0.7142857142857143}]
\draw[->,>=latex] ( 1,0) -- (22,0);
\begin{scope}[draw=blue]
\draw[thick] (3,0) -- (18,0);
\draw[thick] (2.9,0.1) -- (3.0,0.1) -- (3.0,-0.1) -- (2.9,-0.1);
\draw[thick] (17.9,0.1) -- (18.0,0.1) -- (18.0,-0.1) -- (17.9,-0.1);
\node[below,inner sep=3mm] at (3,0) {$3$};
\node[below,inner sep=3mm] at (18,0) {$18$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (17,-0.03) -- (20,-0.03);
\draw[thick] (16.9,0.1) -- (17.0,0.1) -- (17.0,-0.1) -- (16.9,-0.1);
\draw[thick] (19.9,0.1) -- (20.0,0.1) -- (20.0,-0.1) -- (19.9,-0.1);
\node[below,inner sep=3mm] at (17,0) {$17$};
\node[below,inner sep=3mm] at (20,0) {$20$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervOF{17}{18}$ et $I \cup J = \intervOF{3}{20}$.

%%%%%%%%%%%%%%%%%

\item $I=\intervFF{-3}{0}$ et $J=\intervFO{-1}{+\infty}$ % 7

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -5,0) -- (2,0);
\begin{scope}[draw=blue]
\draw[thick] (-3,0) -- (0,0);
\draw[thick] (-2.9,0.1) -- (-3.0,0.1) -- (-3.0,-0.1) -- (-2.9,-0.1);
\draw[thick] (-0.1,0.1) -- (0.0,0.1) -- (0.0,-0.1) -- (-0.1,-0.1);
\node[below,inner sep=3mm] at (-3,0) {$-3$};
\node[below,inner sep=3mm] at (0,0) {$0$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (-1,-0.03) -- (2,-0.03);
\draw[thick] (-0.9,0.1) -- (-1.0,0.1) -- (-1.0,-0.1) -- (-0.9,-0.1);
\draw[thick] (2.1,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (2.1,-0.1);
\node[below,inner sep=3mm] at (-1,0) {$-1$};
\node[below,inner sep=3mm] at (2,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFF{-1}{0}$ et $I \cup J = \intervFO{-3}{+\infty}$.

%%%%%%%%%%%%%%%%

\item $I=\intervFO{-2}{0}$ et $J=\intervFO{0}{+\infty}$ % 8

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -4,0) -- (2,0);
\begin{scope}[draw=blue]
\draw[thick] (-2,0) -- (0,0);
\draw[thick] (-1.9,0.1) -- (-2.0,0.1) -- (-2.0,-0.1) -- (-1.9,-0.1);
\draw[thick] (0.1,0.1) -- (0.0,0.1) -- (0.0,-0.1) -- (0.1,-0.1);
\node[below,inner sep=3mm] at (-2,0) {$-2$};
\node[below,inner sep=3mm] at (0,0) {$0$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (0,-0.03) -- (2,-0.03);
\draw[thick] (0.1,0.1) -- (0.0,0.1) -- (0.0,-0.1) -- (0.1,-0.1);
\draw[thick] (2.1,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (2.1,-0.1);
\node[below,inner sep=3mm] at (0,0) {$0$};
\node[below,inner sep=3mm] at (2,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \varnothing$ et $I \cup J = \intervFO{-2}{+\infty}$.

%%%%%%%%%%%%%%%%

\item $I=\intervOO{7}{18}$ et $J=\intervFO{10}{+\infty}$ %9

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( 5,0) -- (20,0);
\begin{scope}[draw=blue]
\draw[thick] (7,0) -- (18,0);
\draw[thick] (6.9,0.1) -- (7.0,0.1) -- (7.0,-0.1) -- (6.9,-0.1);
\draw[thick] (18.1,0.1) -- (18.0,0.1) -- (18.0,-0.1) -- (18.1,-0.1);
\node[below,inner sep=3mm] at (7,0) {$7$};
\node[below,inner sep=3mm] at (18,0) {$18$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (10,-0.03) -- (20,-0.03);
\draw[thick] (10.1,0.1) -- (10.0,0.1) -- (10.0,-0.1) -- (10.1,-0.1);
\draw[thick] (20.1,0.1) -- (20.0,0.1) -- (20.0,-0.1) -- (20.1,-0.1);
\node[below,inner sep=3mm] at (10,0) {$10$};
\node[below,inner sep=3mm] at (20,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFO{10}{18}$ et $I \cup J = \intervOO{7}{+\infty}$.

%%%%%%%%%%%%%%%

\item $I=\intervOO{-4}{2}$ et $J=\intervFF{2}{5}$ % 10

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -6,0) -- (7,0);
\begin{scope}[draw=blue]
\draw[thick] (-4,0) -- (2,0);
\draw[thick] (-4.1,0.1) -- (-4.0,0.1) -- (-4.0,-0.1) -- (-4.1,-0.1);
\draw[thick] (2.1,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (2.1,-0.1);
\node[below,inner sep=3mm] at (-4,0) {$-4$};
\node[below,inner sep=3mm] at (2,0) {$2$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (2,-0.03) -- (5,-0.03);
\draw[thick] (2.1,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (2.1,-0.1);
\draw[thick] (4.9,0.1) -- (5.0,0.1) -- (5.0,-0.1) -- (4.9,-0.1);
\node[below,inner sep=3mm] at (2,0) {$2$};
\node[below,inner sep=3mm] at (5,0) {$5$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \varnothing$ et $I \cup J = \intervOF{-4}{5}$.

%%%%%%%%%%%%%%

\item $I=\intervOO{-4}{2}$ et $J=\intervOF{2}{5}$ % 11

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -6,0) -- (7,0);
\begin{scope}[draw=blue]
\draw[thick] (-4,0) -- (2,0);
\draw[thick] (-4.1,0.1) -- (-4.0,0.1) -- (-4.0,-0.1) -- (-4.1,-0.1);
\draw[thick] (2.1,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (2.1,-0.1);
\node[below,inner sep=3mm] at (-4,0) {$-4$};
\node[below,inner sep=3mm] at (2,0) {$2$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (2,-0.03) -- (5,-0.03);
\draw[thick] (1.9,0.1) -- (2.0,0.1) -- (2.0,-0.1) -- (1.9,-0.1);
\draw[thick] (4.9,0.1) -- (5.0,0.1) -- (5.0,-0.1) -- (4.9,-0.1);
\node[below,inner sep=3mm] at (2,0) {$2$};
\node[below,inner sep=3mm] at (5,0) {$5$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \varnothing$ et $I \cup J = \intervOO{-4}{2} \cup \intervOF{2}{5}$.

%%%%%%%%%%%%%%

\item $I=\intervFO{-3}{+\infty}$ et $J=\intervOO{-5}{+\infty}$ %12

\begin{tikzpicture}[scale=1, every node/.style={scale=1}]
\draw[->,>=latex] ( -7,0) -- (-1,0);
\begin{scope}[draw=blue]
\draw[thick] (-3,0) -- (-1,0);
\draw[thick] (-2.9,0.1) -- (-3.0,0.1) -- (-3.0,-0.1) -- (-2.9,-0.1);
\draw[thick] (-0.9,0.1) -- (-1.0,0.1) -- (-1.0,-0.1) -- (-0.9,-0.1);
\node[below,inner sep=3mm] at (-3,0) {$-3$};
\node[below,inner sep=3mm] at (-1,0) {$+\infty$};
\end{scope}
\begin{scope}[draw=red]
\draw[thick] (-5,-0.03) -- (-1,-0.03);
\draw[thick] (-5.1,0.1) -- (-5.0,0.1) -- (-5.0,-0.1) -- (-5.1,-0.1);
\draw[thick] (-0.9,0.1) -- (-1.0,0.1) -- (-1.0,-0.1) -- (-0.9,-0.1);
\node[below,inner sep=3mm] at (-5,0) {$-5$};
\node[below,inner sep=3mm] at (-1,0) {$+\infty$};
\end{scope}
\end{tikzpicture}

Donc $I \cap J = \intervFO{-3}{+\infty}$ et $I \cup J = \intervOO{-5}{+\infty}$.

\end{enumerate}
