
\begin{enumerate}
\item $F(x)=5x$.
\item $F(x)=3\times\dfrac{1}{2}x^2+2x=\dfrac{3}{2}x^2+2x$.
\item $F(x)=-8\times\dfrac{1}{2}x^2-3x=-4x^2-3x$.
\item $F(x)=x^3-\dfrac{5}{2}x^2+2x$.
\item $F(x)=-\dfrac{1}{3}\times\dfrac{1}{6}x^6+8\times\dfrac{1}{4}x^4-\dfrac{7}{2}x^2+x=-\dfrac{1}{18}x^6+2x^4-\dfrac{7}{2}x^2+x$.
\item $F(x)=\e^x$.
\item $F(x)=\dfrac{1}{2}\e^{2x}$.
\item $F(x)=\ln\big(x^2+x+1\big)$ car si $u(x)=x^2+x+1$, alors $f(x)=\dfrac{u'(x)}{u(x)}$.
\item $f(x)=-\dfrac{5}{2}\times\dfrac{2x}{x^2+1}=-\dfrac{5}{2}\dfrac{u'}{u}$ avec $u(x)=x^2+1$ donc $F(x)=-\dfrac{5}{2}\ln\big(x^2+1\big)$.
\item $f(x)=-3\times\left(-\dfrac{1}{x^2}\right)$ donc $F(x)=-3\times\dfrac{1}{x}=-\dfrac{3}{x}$.
\end{enumerate}
