
\begin{enumerate}
\item $\ln(8)-\ln(2) = \ln\left(\dfrac{8}{2}\right)=\boxed{\ln(4)}$

\item $\ln(6)+\ln(3)=\ln(6\times3)=\boxed{\ln(18)}$

\item $\ln(25)-\ln(30)+\ln(10) = \ln\left(\dfrac{25}{30}\times 10 \right) = \boxed{\ln\left(\dfrac{25}{3}\right)}$

\item $\ln(50)+\ln(2)-\ln(10) = \ln\left(\dfrac{50\times2}{10}\right)=\boxed{\ln(10)}$

\item $\begin{aligned}[t]
3\ln(4)-\ln(256) & = \ln\big(4^3\big) - \ln(256)\\
				 & = \ln\left( \dfrac{2^6}{2^8} \right)\\
				 & =\boxed{\ln\left(\dfrac{1}{4}\right)}
\end{aligned}$

\item $\begin{aligned}[t]
2\ln(2)-\ln(16)+\ln(128) & =\ln\big(2^2\big) - \ln\big(2^4\big) +\ln\big(2^7\big)\\
						 & = \ln\left(\dfrac{2^2\times2^7}{2^4}\right)\\
						 & = \ln\big(2^5\big)\\
						 & = \boxed{ \ln(32) }
\end{aligned}$
\end{enumerate}
